Pedantic gcc warning: type qualifiers on function return type(Pedantic gcc 警告:函数返回类型的类型限定符)
问题描述
当我第一次使用 GCC 4.3 编译我的 C++ 代码时(在使用 -Wall -Wextra
选项成功编译它并且在 4.1、4.0、3.4 上没有警告之后)我突然明白了warning: type qualifiers ignored on function return type
形式的一堆错误.
When I compiled my C++ code with GCC 4.3 for the first time, (after having compiled it successfully with no warnings on 4.1, 4.0, 3.4 with the -Wall -Wextra
options) I suddenly got a bunch of errors of the form warning: type qualifiers ignored on function return type
.
考虑 temp.cpp
:
class Something
{
public:
const int getConstThing() const {
return _cMyInt;
}
const int getNonconstThing() const {
return _myInt;
}
const int& getConstReference() const {
return _myInt;
}
int& getNonconstReference() {
return _myInt;
}
void setInt(const int newValue) {
_myInt = newValue;
}
Something() : _cMyInt( 3 ) {
_myInt = 2;
}
private:
const int _cMyInt;
int _myInt;
};
运行g++ temp.cpp -Wextra -c -o blah.o
:
temp.cpp:4: warning: type qualifiers ignored on function return type
temp.cpp:7: warning: type qualifiers ignored on function return type
谁能告诉我我做错了什么违反了 C++ 标准?我想当按值返回时,前导 const
是多余的,但我无法理解为什么需要用它生成警告.还有其他地方我应该去掉 const 吗?
Can someone tell me what I am doing wrong that violates the C++ standard? I suppose that when returning by value, the leading const
is superfluous, but I'm having trouble understanding why it's necessary to generate a warning with it. Are there other places where I should leave off the const?
推荐答案
不违反标准.这就是为什么它们是警告而不是错误.
It doesn't violate the standard. That's why they're warnings and not errors.
确实你是对的——前面的 const
是多余的.编译器会警告您,因为您添加了在其他情况下可能有意义的代码,但在这种情况下没有任何意义,并且它希望确保您稍后在返回值最终变成可修改时不会让您失望.
And indeed you're right — the leading const
is superfluous. The compiler warns you because you've added code that in other circumstances might mean something, but in this circumstance means nothing, and it wants to make sure you won't be disappointed later when your return values turn out to be modifiable after all.
这篇关于Pedantic gcc 警告:函数返回类型的类型限定符的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持编程学习网!
本文标题为:Pedantic gcc 警告:函数返回类型的类型限定符
- C语言手把手带你掌握带头双向循环链表 2023-04-03
- C语言详解float类型在内存中的存储方式 2023-03-27
- Qt计时器使用方法详解 2023-05-30
- c++ const 成员函数,返回一个 const 指针.但是返回的指针是什么类型的 const? 2022-10-11
- Easyx实现扫雷游戏 2023-02-06
- 详解C语言中sizeof如何在自定义函数中正常工作 2023-04-09
- ubuntu下C/C++获取剩余内存 2023-09-18
- C++ 数据结构超详细讲解顺序表 2023-03-25
- 我应该为我的项目使用相对包含路径,还是将包含目录放在包含路径上? 2022-10-30
- C语言qsort()函数的使用方法详解 2023-04-26