MongoDB在具有附加字段的对象数组上聚合$lookup-前端问题

MongoDB Aggregate $lookup on array of object with additional field(MongoDB在具有附加字段的对象数组上聚合$lookup)

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问题描述

我有两个不同的集合(下面的示例)方法 &项目.至于现在，我正在为 $lookup 使用 pre 3.6 vanilla 聚合查询:

I have two different collections (example below) methods & items. As for now, I'm using pre 3.6 vanilla aggregation query for $lookup:

MongoPlayground 示例

  {
    $lookup: {
      from: "items",
      localField: "reagents._id",
      foreignField: "_id",
      as: "reagent_items"
    }
  }

问题是，如果我使用它，我会在 $lookup 阶段错过 quantity 字段(来自嵌入的 methods.reagents)原创收藏.现在，我在 lookup 之后立即返回 quantity 但正如我听说的那样，Mongo 从 3.6 引入了一种用于 lookup 查询的新语法，所以问题是:

The problem is that if I am using it, I miss quantity field (from methods.reagents embedded) during $lookup stage from original collection. For now, I return quantity right after lookup but as I heard, Mongo introduced from 3.6 a new syntax for lookup queries, so the question is:

它能否解决我收到以下结果的问题:

Can it solve my problem for receiving the following results:

  {
    "_id": 1,
    "name": "Test",
    "reagent_items": [ // <= the exact schema of what I need after lookup
      {
        "_id": 1,
        "name": "ItemOne",
        "other": "field",
        "quantity": 2 //quantity field from original {array of objects} after lookup
      },
      {
        "_id": 2,
        "name": "ItemTwo",
        "other": "field",
        "quantity": 4 //quantity field from original {array of objects} after lookup
      }
    ],
    "reagents": [ //original reagents field here just for example, we could remove it
      {
        "_id": 1,
        "quantity": 2
      },
      {
        "_id": 2,
        "quantity": 4
      }
    ]
  }

方法

    {
      "_id": 1,
      "name": "Test",
      "reagents": [
        {
          _id: 1,
          quantity: 2
        },
        {
          _id: 2,
          quantity: 4
        }
      ]
    }

项目

    {
      "_id": 1,
      "name": "ItemOne",
      "other": "field"
    },
    {
      "_id": 2,
      "name": "ItemTwo",
      "other": "field"
    }

推荐答案

使用 $map 以及 $arrayElemAt 为每个 reagent_items 找到对应的 reagent 并应用 $mergeObjects 获取一个对象:

Use $map along with $arrayElemAt to find corresponding reagent for each reagent_items and the apply $mergeObjects to get one object:

db.methods.aggregate([
    {
        $lookup: {
            from: "items",
            localField: "reagents._id",
            foreignField: "_id",
            as: "reagent_items"
        }
    },
    {
        $project: {
            _id:1,
            name: 1,
            reagents: 1,
            reagent_items: {
                $map: {
                    input: "$reagent_items",
                    as: "ri",
                    in: {
                        $mergeObjects: [
                            "$$ri",
                            {
                                $arrayElemAt: [ { $filter: { input: "$reagents", cond: { $eq: [ "$$this._id", "$$ri._id" ] } } }, 0 ]
                            }
                        ]
                    }
                }
            }
        }
    }
])

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