使用 for 循环的无符号 int 反向迭代-C/C++实例代码

Unsigned int reverse iteration with for loops(使用 for 循环的无符号 int 反向迭代)

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问题描述

我希望 for 循环中的迭代器变量将迭代反向为 0 作为 unsigned int，我想不出与 i > 类似的比较.-1，就像它是一个 signed int 一样.

I want the iterator variable in a for loop to reverse iterate to 0 as an unsigned int, and I cannot think of a similar comparison to i > -1, as you would do if it was a signed int.

for (unsigned int i = 10; i <= 10; --i) { ... }

但这似乎很不清楚，因为它依赖于无符号整数的数值溢出到10以上.

But this seems very unclear, as it is relying on the numerical overflow of the unsigned integer to be above 10.

也许我只是没有清醒的头脑，但有什么更好的方法来做到这一点......

Maybe I just don't have a clear head, but whats a better way to do this...

免责声明:这只是一个简单的用例，上限10是微不足道的，可以是任何东西，i必须是一个unsigned int.


Disclaimer: this is just a simple use case, the upper limit of 10 is trivial, it could be anything, and i must be an unsigned int. 
推荐答案
可以用
for( unsigned int j = n; j-- > 0; ) { /*...*/ }

它从 n-1 向下迭代到 0.
It iterates from n-1 down to 0.

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