基于另一列中的值创建新的指标列-Python问题

Create new indicator columns based on values in another column(基于另一列中的值创建新的指标列)

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问题描述

我有一些如下所示的数据：

import pandas as pd

fruits = ['apple', 'pear', 'peach']

df = pd.DataFrame({'col1':['i want an apple', 'i hate pears', 'please buy a peach and an apple', 'I want squash']})

print(df.head())

                              col1
0                  i want an apple
1                     i hate pears
2  please buy a peach and an apple
3                    I want squash

我需要一个解决方案，为fruits中的每一项创建一列，并提供一个1或0值来指示col是否包含该值。理想情况下，输出将如下所示：

goal_df = pd.DataFrame({'col1':['i want an apple', 'i hate pears', 'please buy a peach and an apple', 'I want squash'],
                        'apple': [1, 0, 1, 0],
                        'pear': [0, 1, 0, 0],
                        'peach': [0, 0, 1, 0]})

print(goal_df.head())


                              col1  apple  pear  peach
0                  i want an apple      1     0      0
1                     i hate pears      0     1      0
2  please buy a peach and an apple      1     0      1
3                    I want squash      0     0      0

我尝试了一下，但不起作用：

for i in fruits:
    if df['col1'].str.contains(i):
        df[i] = 1
    else:
        df[i] = 0

推荐答案

items = ['apple', 'pear', 'peach']
for it in items:
    df[it] = df['col1'].str.contains(it, case=False).astype(int)

输出：

>>> df
                              col1  apple  pear  peach
0                  i want an apple      1     0      0
1                     i hate pears      0     1      0
2  please buy a peach and an apple      1     0      1
3                    I want squash      0     0      0

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