在 Twig 中过滤和拼接数组

Filtering and splicing an array in Twig(在 Twig 中过滤和拼接数组)

问题描述

我有一个用户记录数组(0 索引，来自数据库查询)，每个记录都包含一个字段数组(按字段名称索引).例如:

I have an array of user records (0 indexed, from a database query), each of which contains an array of fields (indexed by field name). For example:

Array
(
    [0] => Array
        (
            [name] => Fred
            [age] => 42
        )

    [1] => Array
        (
            [name] => Alice
            [age] => 42
        )

    [2] => Array
        (
            [name] => Eve
            [age] => 24
        )

)

在我的 Twig 模板中，我想获取 age 字段为 42 的所有用户，然后将这些用户的 name 字段作为数组返回.然后我可以将该数组传递给 join(<br>) 以每行打印一个名称.

In my Twig template, I want to get all the users where the age field is 42 and then return the name field of those users as an array. I can then pass that array to join(<br>) to print one name per line.

例如，如果年龄是 42 岁，我希望 Twig 输出:

For example, if the age was 42 I would expect Twig to output:

Fred<br>
Alice

这可以在 Twig 中开箱即用，还是我需要编写自定义过滤器?我不确定如何用几句话来描述我想要的东西，所以可能是其他人写了一个过滤器，但我无法通过搜索找到它.

Is this possible to do in Twig out of the box, or would I need to write a custom filter? I'm not sure how to describe what I want in a couple of words so it may be that someone else has written a filter but I can't find it by searching.

推荐答案

最终解决方案是迄今为止发布的内容的混合，并进行了一些更改.伪代码为:

Final solution was a mix of what has been posted so far, with a couple of changes. The pseudocode is:

for each user
  create empty array of matches
  if current user matches criteria then
    add user to matches array
join array of matches

树枝代码:

{% set matched_users = [] %}
  {% for user in users %}
    {% if user.age == 42 %}
      {% set matched_users = matched_users|merge([user.name|e]) %}
    {% endif %}
  {% endfor %}
  {{ matched_users|join('<br>')|raw }}

merge 将只接受 array 或 Traversable 作为参数，因此您必须转换 user.name 通过将字符串包含在 [] 中，将其转换为单元素数组.还需要转义user.name并使用raw，否则<br>会被转换成<br>(在这种情况下，我希望用户名转义，因为它来自不受信任的来源，而换行符是我指定的字符串).

merge will only accept an array or Traversable as the argument so you have to convert the user.name string to a single-element array by enclosing it in []. You also need to escape user.name and use raw, otherwise <br> will be converted into <br> (in this case I want the user's name escaped because it comes from an untrusted source, whereas the line break is a string I've specified).

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