PHP include() with GET attributes (include file.php?q=1)(带有 GET 属性的 PHP include() (include file.php?q=1))
问题描述
我想 include()
一个位于我的服务器上的 php 文件,带有额外的 GET 属性.但它不起作用:
I want to include()
a php file located on my server, with additional GET attributes.
But it won't work:
include('search.php?q=1');
它给出的错误:
PHP Warning: include(): Failed opening './search.php?q=1' for inclusion
似乎它试图打开一个字面上名为search.php?q=1"的文件,而不是打开search.php"文件并向其发送 GET 属性.
Seems like it tries to open a file literally named 'search.php?q=1' instead of opening the 'search.php' file and sending it the GET attributes.
*请注意,如果我不放置任何 GET 属性,它确实有效:
*Note that it does work if I don't put any GET attributes:
include('search.php');
推荐答案
你不想这样做:你必须做一个 http 请求才能传递 GET 参数.您以这种方式调用的 PHP 脚本将在单独的 PHP 进程中运行.
You don't want to do this: You'd have to do a http request to be able to pass GET parameters. A PHP script you call in this way will run in a separate PHP process.
最佳方法是在本地包含文件:
The optimal way is to include the file locally:
include('search.php');
并手动将任何参数传递给它,例如
and to pass any parameters to it manually, like e.g.
$q = "1";
include('search.php'); // expects `$q` parameter
或者,更简洁地,将您在 search.php
中的所有内容放入可以使用参数调用的函数或类中:
or, more cleanly, putting whatever you have in search.php
into a function or class that you can call with a parameter:
include('search.php'); // defines function my_search($q)
my_search(1);
这篇关于带有 GET 属性的 PHP include() (include file.php?q=1)的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持编程学习网!
本文标题为:带有 GET 属性的 PHP include() (include file.php?q=1)


- 没有作曲家的 PSR4 自动加载 2022-01-01
- 如何定位 php.ini 文件 (xampp) 2022-01-01
- 正确分离 PHP 中的逻辑/样式 2021-01-01
- PHP Count 布尔数组中真值的数量 2021-01-01
- SoapClient 设置自定义 HTTP Header 2021-01-01
- Laravel 仓库 2022-01-01
- Mod使用GET变量将子域重写为PHP 2021-01-01
- 从 PHP 中的输入表单获取日期 2022-01-01
- 带有通配符的 Laravel 验证器 2021-01-01
- Oracle 即时客户端 DYLD_LIBRARY_PATH 错误 2022-01-01