How to save multiple inputs of rows in the same column of database?(如何在数据库的同一列中保存多个行的输入?)
问题描述
数据库表
id | title | reading | writing | speaking
form.blade.php
form.blade.php
<table><tr>
<th>Language</th>
<th>Reading</th>
<th>Writing</th>
<th>Speaking</th>
</tr>
<tr>
<td>
<input name="TitleText_1" id="TitleText_1"/></td>
<td>
<select name="ReadingText_1" id="ReadingText_1">
<option value="High">High</option>
<option value="Medium">Medium</option>
<option value="Low">Low</option>
</select>
</td>
<td>
<select name="langWrittingText_1" id="WrittingText_1">
<option value="High">High</option>
<option value="Medium">Medium</option>
<option value="Low">Low</option>
</select>
</td>
<td>
<select name="SpeakingText_1" id="SpeakingText_1">
<option value="High">High</option>
<option value="Medium">Medium</option>
<option value="Low">Low</option>
</select>
</td>
</tr>
<tr>
<td>
<input name="TitleText_2" id="TitleText_2" /></td>
<td>
<select name="ReadingText_2" id="ReadingText_2">
<option value="High">High</option>
<option value="Medium">Medium</option>
<option value="Low">Low</option>
</select>
</td>
<td>
<select name="WrittingText_2" id="WrittingText_2">
<option value="High">High</option>
<option value="Medium">Medium</option>
<option value="Low">Low</option>
</select>
</td>
<td>
<select name="SpeakingText_2" id="SpeakingText_2">
<option value="High">High</option>
<option value="Medium">Medium</option>
<option value="Low">Low</option>
</select>
</td>
语言控制器.php
$languages = Language::create(array
(
'title' => $input['TitleText_1'],
'reading' => $input['ReadingText_1'],
'writting' => $input['WrittingText_1'],
'speaking' => $input['SpeakingText_1'],
$languages->save();
));
我想要将控制器代码保存到数据库中.因为有多个相同标签的输入.
I want what will be the controller code to save into the database. as there are multiple inputs of same label.
如何获取控制器中的所有输入?另外如何将多个输入保存到同一列的数据库中?我是 Laravel 4.2 的新手.
How to get all the inputs in controller? Also how to save multiple inputs into database of same column? I am a newbie of Laravel 4.2.
推荐答案
像这样使用多个同名输入
Use multiple inputs with same name like this
<input name="TitleText[]" />
<select name="ReadingText[]" >
...
<select name="langWrittingText[]">
...
<select name="SpeakingText[]">
...
这样数据就会以数组的形式发布.假设所有的输入/选择都需要用户填写
This way the data will be posted in the form of an array. Assuming that all the inputs/select are required to be filled by the user
在你的控制器中你可以做这样的事情
In your controller you can do something like this
$count = count($input['TitleText']); // here we will know how many entries have been posted
$languages = array();
for($i=0; $i<$count; $i++){
if(!empty($input['TitleText'][$i])){
array_push($languages, array( // iterate through each entry and create an array of inputs
'title' => $input['TitleText'][$i],
'reading' => $input['ReadingText'][$i],
'writting' => $input['WrittingText'][$i],
'speaking' => $input['SpeakingText'][$i]
));
}
}
Languages::insert($languages); // save the array of models at once
希望这会有所帮助.
这篇关于如何在数据库的同一列中保存多个行的输入?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持编程学习网!
本文标题为:如何在数据库的同一列中保存多个行的输入?
- PHP foreach() 与数组中的数组? 2022-01-01
- 如何在 Symfony2 中正确使用 webSockets 2021-01-01
- 覆盖 Magento 社区模块控制器的问题 2022-01-01
- 如何从数据库中获取数据以在 laravel 中查看页面? 2022-01-01
- 使用 GD 和 libjpeg 支持编译 PHP 2022-01-01
- Oracle 即时客户端 DYLD_LIBRARY_PATH 错误 2022-01-01
- 如何使用 Google API 在团队云端硬盘中创建文件夹? 2022-01-01
- PHP - if 语句中的倒序 2021-01-01
- openssl_digest vs hash vs hash_hmac?盐与盐的区别HMAC? 2022-01-01
- Laravel 5:Model.php 中的 MassAssignmentException 2021-01-01