访问在父函数中定义的变量

Is there a way to access $foo from within inner()?

function outer()
{
    $foo = "...";

    function inner()
    {
        // print $foo
    }

    inner();
}

outer();

推荐答案

PHP<5.3 不支持闭包，因此您必须将 $foo 传递给 inner() 或从两个 outer() 内部使 $foo 成为全局变量和内部()(坏).

PHP<5.3 does not support closures, so you'd have to either pass $foo to inner() or make $foo global from within both outer() and inner() (BAD).

在 PHP 5.3 中，你可以做

In PHP 5.3, you can do

function outer()
{
  $foo = "...";
  $inner = function() use ($foo)
  {
    print $foo;
  };
  $inner();
}
outer();
outer();