沃梦达 / 编程问答 / php问题 / 正文

如何最好地将 CakePHP 日期选择器表单数据转换为

How best to convert CakePHP date picker form data to a PHP DateTime object?(如何最好地将 CakePHP 日期选择器表单数据转换为 PHP DateTime 对象?)

本文介绍了如何最好地将 CakePHP 日期选择器表单数据转换为 PHP DateTime 对象?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我在 app/views/mymodel/add.ctp 中这样做:

<?php echo $form->input('Mymodel.mydatefield'); ?>

然后,在app/controllers/mymodel_controller.php:

function add() {
    # ... (if we have some submitted data)
    $datestring = $this->data['Mymodel']['mydatefield']['year'] . '-' .
                  $this->data['Mymodel']['mydatefield']['month'] . '-' .
                  $this->data['Mymodel']['mydatefield']['day'];
    $mydatefield = DateTime::createFromFormat('Y-m-d', $datestring);
}

绝对必须有更好的方法来做到这一点 - 我只是还没有找到 CakePHP 的方法......

There absolutly has to be a better way to do this - I just haven't found the CakePHP way yet...

我想做的是:

function add() {
    # ... (if we have some submitted data)       
    $mydatefield = $this->data['Mymodel']['mydatefiled']; # obviously doesn't work
}

推荐答案

我知道这是一个老问题,但万一其他人来寻找答案:CakePHP 的通用 Model 类有一个方法, ::deconstruct(),用于在内部处理这个必要的逻辑.你可以这样使用它:

I know this is an old question, but in case anyone else comes looking for an answer: CakePHP's generic Model class has a method, ::deconstruct(), that is used to handle this necessary logic internally. You can use it like this:

$stringDate = $this->MyModel->deconstruct('fieldname', $arrayDate)

这篇关于如何最好地将 CakePHP 日期选择器表单数据转换为 PHP DateTime 对象?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持编程学习网!

本文标题为:如何最好地将 CakePHP 日期选择器表单数据转换为