What should we do for nested objects in Room?(我们应该如何处理Room中的嵌套对象?)
本文介绍了我们应该如何处理Room中的嵌套对象?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
如果下面有类似我的JSON结构的结构,我们应该如何创建实体类?没有这样的例子。虽然在很久以前写的文章中,@Embeded用于内部数组,但现在使用的是类似Converter的结构。我们应该用哪一个呢?这些是做什么用的?如何创建我的类型的结构?请使用Java提供帮助
此处提供了所有必需的结构:https://github.com/theoyuncu8/roomdb
JSON数据
{
"MyData": [
{
"food_id": "1",
"food_name": "Food 1",
"food_image": "imageurl",
"food_kcal": "32",
"food_url": "url",
"food_description": "desc",
"carb_percent": "72",
"protein_percent": "23",
"fat_percent": "4",
"units": [
{
"unit": "Unit A",
"amount": "735.00",
"calory": "75.757",
"calcium": "8.580",
"carbohydrt": "63.363",
"cholestrl": "63.0",
"fiber_td": "56.12",
"iron": "13.0474",
"lipid_tot": "13.01",
"potassium": "11.852",
"protein": "717.1925",
"sodium": "112.02",
"vit_a_iu": "110.7692",
"vit_c": "110.744"
},
{
"unit": "Unit C",
"amount": "32.00",
"calory": "23.757",
"calcium": "53.580",
"carbohydrt": "39.363",
"cholestrl": "39.0",
"fiber_td": "93.12",
"iron": "93.0474",
"lipid_tot": "93.01",
"potassium": "9.852",
"protein": "72.1925",
"sodium": "10.0882",
"vit_a_iu": "80.7692",
"vit_c": "80.744"
}
]
},
{
"food_id": "2",
"food_name": "Food 2",
"food_image": "imageurl",
"food_kcal": "50",
"food_url": "url",
"food_description": "desc",
"carb_percent": "25",
"protein_percent": "14",
"fat_percent": "8",
"units": [
{
"unit": "Unit A",
"amount": "25.00",
"calory": "25.757",
"calcium": "55.580",
"carbohydrt": "53.363",
"cholestrl": "53.0",
"fiber_td": "53.12",
"iron": "53.0474",
"lipid_tot": "53.01",
"potassium": "17.852",
"protein": "757.1925",
"sodium": "122.02",
"vit_a_iu": "10.7692",
"vit_c": "10.744"
},
{
"unit": "Unit C",
"amount": "2.00",
"calory": "2.757",
"calcium": "5.580",
"carbohydrt": "3.363",
"cholestrl": "3.0",
"fiber_td": "3.12",
"iron": "3.0474",
"lipid_tot": "3.01",
"potassium": "77.852",
"protein": "77.1925",
"sodium": "12.02",
"vit_a_iu": "0.7692",
"vit_c": "0.744"
},
{
"unit": "Unit G",
"amount": "1.00",
"calory": "2.1",
"calcium": "0.580",
"carbohydrt": "0.363",
"cholestrl": "0.0",
"fiber_td": "0.12",
"iron": "0.0474",
"lipid_tot": "0.01",
"potassium": "5.852",
"protein": "0.1925",
"sodium": "1.02",
"vit_a_iu": "0.7692",
"vit_c": "0.744"
}
]
}
]
}
实体类
食品类
public class Foods {
@SerializedName("food_id")
@Expose
private String foodId;
@SerializedName("food_name")
@Expose
private String foodName;
@SerializedName("food_image")
@Expose
private String foodImage;
@SerializedName("food_kcal")
@Expose
private String foodKcal;
@SerializedName("food_url")
@Expose
private String foodUrl;
@SerializedName("food_description")
@Expose
private String foodDescription;
@SerializedName("carb_percent")
@Expose
private String carbPercent;
@SerializedName("protein_percent")
@Expose
private String proteinPercent;
@SerializedName("fat_percent")
@Expose
private String fatPercent;
// here
@SerializedName("units")
@Expose
private List<FoodUnitsData> units = null;
// getter setter
}
FoodUnitsData类
public class FoodUnitsData {
@SerializedName("unit")
@Expose
private String unit;
@SerializedName("amount")
@Expose
private String amount;
@SerializedName("calory")
@Expose
private String calory;
@SerializedName("calcium")
@Expose
private String calcium;
@SerializedName("carbohydrt")
@Expose
private String carbohydrt;
@SerializedName("cholestrl")
@Expose
private String cholestrl;
@SerializedName("fiber_td")
@Expose
private String fiberTd;
@SerializedName("iron")
@Expose
private String iron;
@SerializedName("lipid_tot")
@Expose
private String lipidTot;
@SerializedName("potassium")
@Expose
private String potassium;
@SerializedName("protein")
@Expose
private String protein;
@SerializedName("sodium")
@Expose
private String sodium;
@SerializedName("vit_a_iu")
@Expose
private String vitAIu;
@SerializedName("vit_c")
@Expose
private String vitC;
// getter setter
}
推荐答案
这些是做什么的?
TypeConverter用于将Room无法处理的类型转换为它可以处理的类型(字符串、基元、整数类型(如Integer、Long)、小数类型(如Double、Float))。
@Embedded基本上表示包含@Embedded类的成员变量作为列。例如@Embedded FoodUnitsData foodUnitsData;
。
从房间角度测试/验证架构
使用上面的类以及用@Database(FoodDatabase)注释的类中定义的实体,最好编译/生成项目并修复Room抱怨的任何问题(在本例中没有)。
因此有FoodDataabse为:-
@Database(entities = {Foods.class, FoodUnitsDataEntity.class /*<<<<<<<<<< ADDED*
沃梦达教程
本文标题为:我们应该如何处理Room中的嵌套对象?
猜你喜欢
- 如何指定 CORS 的响应标头? 2022-01-01
- Eclipse 的最佳 XML 编辑器 2022-01-01
- 转换 ldap 日期 2022-01-01
- 未找到/usr/local/lib 中的库 2022-01-01
- 如何使 JFrame 背景和 JPanel 透明且仅显示图像 2022-01-01
- 获取数字的最后一位 2022-01-01
- 在 Java 中,如何将 String 转换为 char 或将 char 转换 2022-01-01
- 将 Java Swing 桌面应用程序国际化的最佳实践是什么? 2022-01-01
- java.lang.IllegalStateException:Bean 名称“类别"的 BindingResult 和普通目标对象都不能用作请求属性 2022-01-01
- GC_FOR_ALLOC 是否更“严重"?在调查内存使用情况时? 2022-01-01