MySQL:使用来自查询的信息创建一个新表-数据库问题

MySQL: Creating a new table with information from a query(MySQL:使用来自查询的信息创建一个新表)

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问题描述

在 MySQL 中，我想创建一个包含此查询中所有信息的新表:

In MySQL, I would like to create a new table with all the information in this query:

select * into consultaa2 from SELECT
 CONCAT(    'UPDATE customers SET
 customers_default_address_id= ',    
 (SELECT a.address_book_id FROM
 address_book a where
 c.customers_id=a.customers_id order by
 address_book_id desc limit 1),    '
 WHERE customers_id = ', customers_id,
 ';') AS sql_statement FROM customers c
 where c.customers_id > 3894;

查询太长，浏览器无法显示连接，我需要它来进行更新.

The query is too long for the browser to show the concat and I need this to make this updates.

推荐答案

*请注意，此方法不会创建表(根据 OP 标题).为此，请参阅此答案.*

使用来自查询的信息插入表的格式为

Inserting into a table with information from a query is of the format

INSERT INTO <TABLE-1> 
SELECT * FROM <TABLE-2>

在你的情况下，它会是

insert into consultaa2 
SELECT CONCAT( 'UPDATE customers SET customers_default_address_id= ',
(SELECT a.address_book_id FROM address_book a where c.customers_id=a.customers_id order by address_book_id desc limit 1), ' WHERE customers_id = ', customers_id, ';') AS sql_statement FROM customers c where c.customers_id > 3894;

只需确保要插入的表中的列与选择查询返回的列匹配即可.

Just make sure the columns in the table you are inserting into and the columns returned from the select query match.

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