Oracle 在所有表的所有列中搜索字符串-数据库问题

Oracle Search all tables all columns for string(Oracle 在所有表的所有列中搜索字符串)

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问题描述

我需要在我们的 oracle 数据库中搜索所有表和列中的字符串.我在网上找到了以下查询，但是当我执行它时出现以下错误

I need to search our oracle database for a string in all tables and columns. I have the below query I found online but when I execute it I get the following error

感谢任何帮助

ORA-06550: line 6, column 31:
PL/SQL: ORA-00904: "COLUMN_NAME": invalid identifier
ORA-06550: line 6, column 12:
PL/SQL: SQL Statement ignored
ORA-06550: line 8, column 30:
PLS-00364: loop index variable 'T' use is invalid
ORA-06550: line 7, column 4:
PL/SQL: Statement ignored
ORA-06550: line 12, column 38:
PLS-00364: loop index variable 'T' use is invalid
ORA-06550: line 12, column 16:
PL/SQL: Statement ignored

BEGIN  
  FOR t IN (SELECT table_name, column_name FROM all_tables) LOOP   
   EXECUTE IMMEDIATE    
    'SELECT COUNT(*) FROM '||t.table_name||' WHERE '||t.column_name||' = :1'   
     INTO match_count  
       USING v_search_string; 
          IF match_count > 0 THEN 
               dbms_output.put_line( t.table_name ||' '||t.column_name||' '||match_count );
           END IF; 
  END LOOP;
END;
/

推荐答案

至少需要查询ALL_TAB_COLUMNS，而不是ALL_TABLES

At a minimum, you need to query ALL_TAB_COLUMNS, not ALL_TABLES

DECLARE
  match_count integer;
  v_search_string varchar2(4000) := <<string you want to search for>>;
BEGIN  
  FOR t IN (SELECT owner, table_name, column_name FROM all_tab_columns) LOOP   
    EXECUTE IMMEDIATE    
      'SELECT COUNT(*) FROM '||t.owner || '.' || t.table_name||
      ' WHERE '||t.column_name||' = :1'   
       INTO match_count  
      USING v_search_string; 
    IF match_count > 0 THEN 
      dbms_output.put_line( t.owner || '.' || t.table_name ||' '||t.column_name||' '||match_count );
    END IF; 
  END LOOP;
END;
/

然而，如果您正在寻找一个字符串，您几乎肯定希望限制自己寻找可以存储字符串的列.例如，在 DATE 列中搜索字符串是没有意义的.除非您对 BLOB 列包含的内容以及解析 BLOB 列的二进制格式的能力有大量先验知识，否则在 BLOB 列中搜索字符串是没有意义的.鉴于此，我怀疑您想要更像

If you are looking for a string, however, you would almost certainly want to restrict yourself to looking for columns that could store a string. It wouldn't make sense, for example, to search a DATE column for a string. And unless you have a great deal of a priori knowledge about what a BLOB column contains and the ability to parse the BLOB column's binary formatting, it wouldn't make sense to search a BLOB column for a string. Given that, I suspect you want something more like

DECLARE
  match_count integer;
  v_search_string varchar2(4000) := <<string you want to search for>>;
BEGIN  
  FOR t IN (SELECT owner,
                   table_name, 
                   column_name 
              FROM all_tab_columns
             WHERE data_type in ('CHAR', 'VARCHAR2', 'NCHAR', 'NVARCHAR2', 
                                 'CLOB', 'NCLOB') ) 
  LOOP   
    BEGIN
      EXECUTE IMMEDIATE    
        'SELECT COUNT(*) FROM '||t.owner || '.' || t.table_name||
        ' WHERE '||t.column_name||' = :1'   
         INTO match_count  
        USING v_search_string; 
      IF match_count > 0 THEN 
        dbms_output.put_line( t.owner || '.' || t.table_name ||' '||t.column_name||' '||match_count );
      END IF; 
    EXCEPTION
      WHEN others THEN
        dbms_output.put_line( 'Error encountered trying to read ' ||
                              t.column_name || ' from ' || 
                              t.owner || '.' || t.table_name );
    END;
  END LOOP;
END;
/

当然，这会非常慢——您需要对每个表中的每个字符串列进行一次全面扫描.对于中等大的表和中等数量的字符串列，这可能需要很长时间.

Of course, this is going to be insanely slow-- you'd full scan every table once for every string column in the table. With moderately large tables and a moderate number of string columns, that is likely to take quite a while.

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