获取 Azure Function App v2 的根目录

Get root directory of Azure Function App v2(获取 Azure Function App v2 的根目录)

问题描述

我构建了一个 Azure Function App (v2).所有功能所需的配置任务都在一个结构如下的 Setup 类中完成:

I build an Azure Function App (v2). Configuration tasks necessary for all functions are done in a Setup class that is structured like the following:

[assembly: WebJobsStartup(typeof(Startup))]

internal class Startup : IWebJobsStartup
{
  public void Configure(IWebJobsBuilder builder)
  {
    Configuration = new ConfigurationBuilder()
                      .SetBasePath(<functionAppDirectory>)
                      .AddJsonFile("local.settings.json")
                      .Build();
    builder.AddDependencyInjection(ConfigureServices);  
  }

  public IConfiguration Configuration { get; set; }

  private void ConfigureServices(IServiceCollection services)
  {
    var connection = Configuration.GetConnectionString("<myconnection-string>");
    ...
  }
}

在 ConfigureServices 我想从配置文件中读取一个连接字符串.为此，函数应用基本文件夹已使用 SetBasePath 指定.但我发现没有办法访问这条路径.根据 https://github.com/Azure/azure-functions-host/wiki/Retrieving-information-about-the-currently-running-function 可以将 ExecutionContext 注入到包含路径的函数中需要.但是如何在我的 Startup 类中访问 ExecutionContext?

In ConfigureServices I want to read a connection string from a configuration file. For that the function app base folder has be specified with SetBasePath. But I found no way to get access to this path. According to https://github.com/Azure/azure-functions-host/wiki/Retrieving-information-about-the-currently-running-function an ExecutionContext can be injected in a function, which contains the path need. But how do I access ExecutionContext in my Startup class?

推荐答案

你可以在你的启动文件中使用这段代码.我今天刚刚为我的项目测试了它，它适用于云和本地.

You can use this piece of code in your startup file. I have just tested it today for my project and it works on both cloud and local.

var executioncontextoptions = builder.Services.BuildServiceProvider()
    .GetService<IOptions<ExecutionContextOptions>>().Value;
var currentDirectory = executioncontextoptions.AppDirectory;

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