Find string in vector of strings case insensitive c++(在不区分大小写的字符串向量中查找字符串 C++)
问题描述
I have
std::vector<std::string> vec;
std::string myString;
and I need to find out if myString
is in vec
using case insensitive comaprisons.
I know I can use
find(vec.begin(), vec.end(), myString) != vec.end())
to answer the question "is myString in vec?" but that will do case sensitive comparisons. I need case insensitive comparisons.
The position is not important, I just want to know if myString is in vec or not.
Or, for a much smaller and easier-to-read solution, Boost!
// #include <algorithm>
// #include <boost/algorithm/string/predicate.hpp>
const auto it = std::find_if(
std::begin(vec),
std::end(vec),
[&myString](const auto& str) { return boost::iequals(myString, str); }
);
const bool found = (it != std::end(vec));
这篇关于在不区分大小写的字符串向量中查找字符串 C++的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持编程学习网!
本文标题为:在不区分大小写的字符串向量中查找字符串 C++


- 哪个更快:if (bool) 或 if(int)? 2022-01-01
- OpenGL 对象的 RAII 包装器 2021-01-01
- 如何提取 __VA_ARGS__? 2022-01-01
- 将 hdc 内容复制到位图 2022-09-04
- XML Schema 到 C++ 类 2022-01-01
- 使用 __stdcall & 调用 DLLVS2013 中的 GetProcAddress() 2021-01-01
- 从父 CMakeLists.txt 覆盖 CMake 中的默认选项(...)值 2021-01-01
- DoEvents 等效于 C++? 2021-01-01
- GDB 不显示函数名 2022-01-01
- 将函数的返回值分配给引用 C++? 2022-01-01