Pugixml - 使用前缀映射和没有前缀 mappig 解析命名空间

Pugixml - parse namespace with prefix mapping and without prefix mappig(Pugixml - 使用前缀映射和没有前缀 mappig 解析命名空间)

问题描述

我有一个客户端应用程序，它解析从 2 个不同服务器发送的 xml 响应.我称它们为服务器 A 和服务器 B.

I have a client application that parses xml responses that are sent from 2 different servers. I call them server A and server B.

服务器 A 响应其中一个请求，响应如下:

Server A responds to one of the request with a response as below:

<?xml version="1.0" encoding="UTF-8"?>
    <D:multistatus xmlns:D="DAV:">
    <D:response>
    <D:href>/T12.txt</D:href>
    <D:propstat>
    <D:prop>
    <local-modification-time xmlns="urn:abc.com:webdrive">1389692809</local-modification-time>
    </D:prop>

    <D:status>HTTP/1.1 200 OK</D:status>

    </D:propstat>
</D:response>
</D:multistatus>

服务器 B 响应其中一个请求，响应如下:

Server B responds to one of the request with a response as below:

<?xml version="1.0" encoding="UTF-8"?>
    <D:multistatus xmlns:D="DAV:">
    <D:response>
    <D:href>/T12.txt</D:href>
    <D:propstat>
    <D:prop>
    <O:local-modification-time xmlns:O="urn:abc.com:webdrive">1389692809</O:local-modification-time>
    </D:prop>

    <D:status>HTTP/1.1 200 OK</D:status>

    </D:propstat>
</D:response>
</D:multistatus>

如果您观察两个服务器之间的差异，serverA 不会发送命名空间和前缀之间的映射，但 serverB 会发送(查看 local-modification-time 标记).如何编写通用客户端解析逻辑，以通用处理这两种情况.任何示例代码都会有很大帮助.

If you observer the difference between the two servers, serverA does not send a mapping between namespace and prefix, but serverB does (look at local-modification-time tag). How can I write a generic client parsing logic, to handle both these scenarios generically. Any sample code would be of great help.

谢谢，-桑迪普

推荐答案

我认为最好的办法是忽略命名空间并通过本地名称查找节点.您可以像这样使用 XPath:

I think your best bet is to just ignore namespaces and find the node by local name. You can do it with XPath like this:

node.select_single_node(".[local-name()='local-modification-time']")

或者你可以像这样使用 C++:

Or you can just use C++ like this:

pugi::xml_node child_by_local_name(pugi::xml_node node, const char* name)
{
    for (pugi::xml_node child = node.first_child(); child; child = child.next_sibling())
    {
        if (strcmp(child.name(), name) == 0)
            return child;

        const char* colon = strchr(child.name(), ':');

        if (colon && strcmp(colon + 1, name) == 0)
            return child;
    }

    return pugi::xml_node();
}

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