'int [0]' C++ 的初始化程序太多

too many initializers for #39;int [0]#39; c++(int [0] C++ 的初始化程序太多)

问题描述

第一:

int k[] ={1,2,3,4,5};

第二:

struct slk
{
    int k[] ={1,2,3,4,5};
};

对于这两个语句，为什么第一个通过编译但第二个给我

for those two statements, why does the first one pass the compilation but the second one give me

错误:'int [0]' 的初始化程序太多.如果我设置 k[5]，编译将通过；

error:too many initializers for 'int [0]'. the compilation would passed if I set k[5];

这个错误信息是什么意思?注意:在 GNU GCC 版本 4.7.2 上测试的代码

What does this error message means? Note: code tested on GNU GCC version 4.7.2

推荐答案

在 C++11 中，允许使用类内成员初始化器，但基本上与在成员初始化列表中初始化相同.因此，必须明确说明数组的大小.

In C++11, in-class member initializers are allowed, but basically act the same as initializing in a member initialization list. Therefore, the size of the array must be explicitly stated.

Stroustrup 在他的网站这里有一个简短的解释.

Stroustrup has a short explanation on his website here.

错误消息意味着您为长度为 0 的数组提供了太多项，这正是 int [] 在该上下文中的计算结果.

The error message means that you are providing too many items for an array of length 0, which is what int [] evaluates to in that context.

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