Using OpenGL glutDisplayFunc within class(在类中使用 OpenGL glutDisplayFunc)
问题描述
我创建了一个 C++ 类 (myPixmap) 来封装由 OpenGL GLUT 工具包执行的工作.类的
display()
成员函数包含设置 GLUT 所需的大部分代码.
I've created a C++ class (myPixmap
) to encapsulate the work performed by the OpenGL GLUT toolkit. The display()
member function of the class contains most of the code required to set up GLUT.
void myPixmap::display()
{
// open an OpenGL window if it hasn't already been opened
if (!openedWindow)
{
// command-line arguments to appease glut
char *argv[] = {"myPixmap"};
int argc = 1;
glutInit(&argc, argv);
glutInitDisplayMode(GLUT_SINGLE | GLUT_RGB);
glutInitWindowSize(640, 480);
glutInitWindowPosition(30, 30);
glutCreateWindow("Experiment");
glutDisplayFunc(draw);
glClearColor(0.9f, 0.9f, 0.9f, 0.0);
glClear(GL_COLOR_BUFFER_BIT);
glutMainLoop();
openedWindow = true;
}
}
传递给glutDisplayFunc()
的显示函数是该类的另一个成员函数:
The display function passed to glutDisplayFunc()
is another member function of the class:
void myPixmap::draw(void)
{
glDrawPixels( m,n,GL_RGB,GL_UNSIGNED_BYTE, pixel );
}
然而,Mac OS X 10.6.4 上的 gcc 4.2.1 拒绝编译此代码,声称:
However, gcc 4.2.1 on Mac OS X 10.6.4 refuses to compile this code, claiming that:
<代码>void (myPixmap::)()"类型的参数与void (*)()"不匹配
有没有办法在类的成员函数内使用 GLUT 工具包,或者我必须在程序的 main
函数内调用所有的 GLUT 函数?
Is there a way to use the GLUT toolkit inside a member function of a class, or must I call all GLUT functions within the main
function of the program?
推荐答案
问题是指向实例绑定成员函数的指针必须包含 this
指针.OpenGL 是一个 C API,对 this
指针一无所知.您必须使用静态成员函数(它不需要实例,因此不需要 this
),并设置一些静态数据成员(以访问实例)才能使用 glutDisplayFunc
.
The problem is that a pointer to an instance bound member function has to include the this
pointer. OpenGL is a C API, and knows nothing about this
pointers. You'll have to use a static member function (which doesn't require an instance, and thus no this
), and set some static data members (to access the instance) in order to use glutDisplayFunc
.
class myPixmap
{
private:
static myPixmap* currentInstance;
static void drawCallback()
{
currentInstance->draw();
}
void setupDrawCallback()
{
currentInstance = this;
::glutDisplayFunc(myPixmap::drawCallback);
}
};
您可能还会遇到 C 链接与 C++ 链接的问题,在这种情况下,您必须尝试使用 extern "C"
.如果是这样,您可能必须使用全局函数,而不是静态成员函数作为回调,并让 那个 调用 myPixmap::draw
.类似的东西:
You may also have problems with C linkage vs C++ linkage, in which case you'll have to play around with extern "C"
. If so, you might have to use a global function, rather than a static member function as your callback, and have that call myPixmap::draw
. Something like:
class myPixmap
{
public:
void draw();
private:
void setupDrawCallback();
};
myPixmap* g_CurrentInstance;
extern "C"
void drawCallback()
{
g_CurrentInstance->draw();
}
void myPixmap::setupDrawCallback();
{
::g_CurrentInstance = this;
::glutDisplayFunc(::drawCallback);
}
考虑到所有这些,请尝试进行尽可能少的更改,因为这对于处理 OpenGL 作为 C API 来说确实有点麻烦.
With all of this, try to make as few changes as possible, since this is really kind of a kludge to deal w/ OpenGL being a C API.
如果你想要多个实例(我认为大多数使用 GLUT 的人不会创建多个实例,但也许你是),你必须找出一个使用 std::map 来检索实例的解决方案:>
If you want multiple instances (I don't think most people using GLUT make multiple instances, but maybe you are), you'll have to figure out a solution using a std::map to retrieve the instance:
static std::map<int, myPixmap> instanceMap;
从哪里获得 int
来解析 哪个 实例,我不确定:)
Where you'd get the int
to resolve which instance, I am not sure :)
仅供参考,您应该以这种方式定义不带参数的函数:
FYI, you should define functions that take no parameters this way:
void some_function() { }
不是
void some_function(void) { }
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本文标题为:在类中使用 OpenGL glutDisplayFunc
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