C++ can compilers inline a function pointer?(C++ 编译器可以内联函数指针吗?)
问题描述
假设我有一个函数 functionProxy
,它接受一个泛型参数 function
并调用它的 operator()
:
Suppose I've got a function functionProxy
that takes a generic parameter function
and call its operator()
:
template< typename Function > void functionProxy( Function function ) {
function();
}
<小时>
传递给它的对象可能是:
The object passed to it may be:
一个函子:
a functor:
struct Functor {
void operator()() const {
std::cout << "functor!" << std::endl;
}
};
一个函数:
a function:
void function( ) {
std::cout << "function!" << std::endl;
}
一个 (C++0x) lambda 函数:
a (C++0x) lambda function:
[](){ std::cout << "lambda!" << std::endl; }
int main( )
{
functionProxy( Functor() );
functionProxy( function );
functionProxy( [](){ std::cout << "lambda!" << std::endl; } );
return 0;
}
<小时>
在上述所有情况下,编译器是否能够将 function
内联到 functionProxy
中?
推荐答案
没问题.
它知道function
的值和它传递给它的值是一样的,知道函数的定义,所以直接内联替换定义,直接调用函数.
It knows the value of function
is the same as the value it passes it, knows the definition of the function, so just replaces the definition inline and calls the function directly.
我想不出编译器不会内联单行函数调用的情况,它只是用函数调用替换函数调用,没有可能的损失.
I can't think of a condition where a compiler won't inline a one-line function call, it's just replacing a function call with a function call, no possible loss.
鉴于此代码:
#include <iostream>
template <typename Function>
void functionProxy(Function function)
{
function();
}
struct Functor
{
void operator()() const
{
std::cout << "functor!" << std::endl;
}
};
void function()
{
std::cout << "function!" << std::endl;
}
//#define MANUALLY_INLINE
#ifdef MANUALLY_INLINE
void test()
{
Functor()();
function();
[](){ std::cout << "lambda!" << std::endl; }();
}
#else
void test()
{
functionProxy(Functor());
functionProxy(function);
functionProxy([](){ std::cout << "lambda!" << std::endl; });
}
#endif
int main()
{
test();
}
定义 MANUALLY_INLINE
后,我们得到:
With MANUALLY_INLINE
defined, we get this:
test:
00401000 mov eax,dword ptr [__imp_std::endl (402044h)]
00401005 mov ecx,dword ptr [__imp_std::cout (402058h)]
0040100B push eax
0040100C push offset string "functor!" (402114h)
00401011 push ecx
00401012 call std::operator<<<std::char_traits<char> > (401110h)
00401017 add esp,8
0040101A mov ecx,eax
0040101C call dword ptr [__imp_std::basic_ostream<char,std::char_traits<char> >::operator<< (40204Ch)]
00401022 mov edx,dword ptr [__imp_std::endl (402044h)]
00401028 mov eax,dword ptr [__imp_std::cout (402058h)]
0040102D push edx
0040102E push offset string "function!" (402120h)
00401033 push eax
00401034 call std::operator<<<std::char_traits<char> > (401110h)
00401039 add esp,8
0040103C mov ecx,eax
0040103E call dword ptr [__imp_std::basic_ostream<char,std::char_traits<char> >::operator<< (40204Ch)]
00401044 mov ecx,dword ptr [__imp_std::endl (402044h)]
0040104A mov edx,dword ptr [__imp_std::cout (402058h)]
00401050 push ecx
00401051 push offset string "lambda!" (40212Ch)
00401056 push edx
00401057 call std::operator<<<std::char_traits<char> > (401110h)
0040105C add esp,8
0040105F mov ecx,eax
00401061 call dword ptr [__imp_std::basic_ostream<char,std::char_traits<char> >::operator<< (40204Ch)]
00401067 ret
没有,这个:
test:
00401000 mov eax,dword ptr [__imp_std::endl (402044h)]
00401005 mov ecx,dword ptr [__imp_std::cout (402058h)]
0040100B push eax
0040100C push offset string "functor!" (402114h)
00401011 push ecx
00401012 call std::operator<<<std::char_traits<char> > (401110h)
00401017 add esp,8
0040101A mov ecx,eax
0040101C call dword ptr [__imp_std::basic_ostream<char,std::char_traits<char> >::operator<< (40204Ch)]
00401022 mov edx,dword ptr [__imp_std::endl (402044h)]
00401028 mov eax,dword ptr [__imp_std::cout (402058h)]
0040102D push edx
0040102E push offset string "function!" (402120h)
00401033 push eax
00401034 call std::operator<<<std::char_traits<char> > (401110h)
00401039 add esp,8
0040103C mov ecx,eax
0040103E call dword ptr [__imp_std::basic_ostream<char,std::char_traits<char> >::operator<< (40204Ch)]
00401044 mov ecx,dword ptr [__imp_std::endl (402044h)]
0040104A mov edx,dword ptr [__imp_std::cout (402058h)]
00401050 push ecx
00401051 push offset string "lambda!" (40212Ch)
00401056 push edx
00401057 call std::operator<<<std::char_traits<char> > (401110h)
0040105C add esp,8
0040105F mov ecx,eax
00401061 call dword ptr [__imp_std::basic_ostream<char,std::char_traits<char> >::operator<< (40204Ch)]
00401067 ret
一样.(与 MSVC 2010 一起编译,原版.)
The same. (Compiled with MSVC 2010, vanilla Release.)
这篇关于C++ 编译器可以内联函数指针吗?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持编程学习网!
本文标题为:C++ 编译器可以内联函数指针吗?
- 从python回调到c++的选项 2022-11-16
- STL 中有 dereference_iterator 吗? 2022-01-01
- 如何对自定义类的向量使用std::find()? 2022-11-07
- C++ 协变模板 2021-01-01
- 静态初始化顺序失败 2022-01-01
- 近似搜索的工作原理 2021-01-01
- Stroustrup 的 Simple_window.h 2022-01-01
- 使用/clr 时出现 LNK2022 错误 2022-01-01
- 与 int by int 相比,为什么执行 float by float 矩阵乘法更快? 2021-01-01
- 一起使用 MPI 和 OpenCV 时出现分段错误 2022-01-01